Integrand size = 10, antiderivative size = 119 \[ \int x^3 \text {arcsinh}(a x)^n \, dx=\frac {2^{-2 (3+n)} (-\text {arcsinh}(a x))^{-n} \text {arcsinh}(a x)^n \Gamma (1+n,-4 \text {arcsinh}(a x))}{a^4}-\frac {2^{-4-n} (-\text {arcsinh}(a x))^{-n} \text {arcsinh}(a x)^n \Gamma (1+n,-2 \text {arcsinh}(a x))}{a^4}-\frac {2^{-4-n} \Gamma (1+n,2 \text {arcsinh}(a x))}{a^4}+\frac {2^{-2 (3+n)} \Gamma (1+n,4 \text {arcsinh}(a x))}{a^4} \]
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Time = 0.13 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {5780, 5556, 3389, 2212} \[ \int x^3 \text {arcsinh}(a x)^n \, dx=\frac {2^{-2 (n+3)} \text {arcsinh}(a x)^n (-\text {arcsinh}(a x))^{-n} \Gamma (n+1,-4 \text {arcsinh}(a x))}{a^4}-\frac {2^{-n-4} \text {arcsinh}(a x)^n (-\text {arcsinh}(a x))^{-n} \Gamma (n+1,-2 \text {arcsinh}(a x))}{a^4}-\frac {2^{-n-4} \Gamma (n+1,2 \text {arcsinh}(a x))}{a^4}+\frac {2^{-2 (n+3)} \Gamma (n+1,4 \text {arcsinh}(a x))}{a^4} \]
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Rule 2212
Rule 3389
Rule 5556
Rule 5780
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int x^n \cosh (x) \sinh ^3(x) \, dx,x,\text {arcsinh}(a x)\right )}{a^4} \\ & = \frac {\text {Subst}\left (\int \left (-\frac {1}{4} x^n \sinh (2 x)+\frac {1}{8} x^n \sinh (4 x)\right ) \, dx,x,\text {arcsinh}(a x)\right )}{a^4} \\ & = \frac {\text {Subst}\left (\int x^n \sinh (4 x) \, dx,x,\text {arcsinh}(a x)\right )}{8 a^4}-\frac {\text {Subst}\left (\int x^n \sinh (2 x) \, dx,x,\text {arcsinh}(a x)\right )}{4 a^4} \\ & = -\frac {\text {Subst}\left (\int e^{-4 x} x^n \, dx,x,\text {arcsinh}(a x)\right )}{16 a^4}+\frac {\text {Subst}\left (\int e^{4 x} x^n \, dx,x,\text {arcsinh}(a x)\right )}{16 a^4}+\frac {\text {Subst}\left (\int e^{-2 x} x^n \, dx,x,\text {arcsinh}(a x)\right )}{8 a^4}-\frac {\text {Subst}\left (\int e^{2 x} x^n \, dx,x,\text {arcsinh}(a x)\right )}{8 a^4} \\ & = \frac {4^{-3-n} (-\text {arcsinh}(a x))^{-n} \text {arcsinh}(a x)^n \Gamma (1+n,-4 \text {arcsinh}(a x))}{a^4}-\frac {2^{-4-n} (-\text {arcsinh}(a x))^{-n} \text {arcsinh}(a x)^n \Gamma (1+n,-2 \text {arcsinh}(a x))}{a^4}-\frac {2^{-4-n} \Gamma (1+n,2 \text {arcsinh}(a x))}{a^4}+\frac {4^{-3-n} \Gamma (1+n,4 \text {arcsinh}(a x))}{a^4} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 99, normalized size of antiderivative = 0.83 \[ \int x^3 \text {arcsinh}(a x)^n \, dx=\frac {4^{-3-n} (-\text {arcsinh}(a x))^{-n} \left (\text {arcsinh}(a x)^n \Gamma (1+n,-4 \text {arcsinh}(a x))-2^{2+n} \text {arcsinh}(a x)^n \Gamma (1+n,-2 \text {arcsinh}(a x))+(-\text {arcsinh}(a x))^n \left (-2^{2+n} \Gamma (1+n,2 \text {arcsinh}(a x))+\Gamma (1+n,4 \text {arcsinh}(a x))\right )\right )}{a^4} \]
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\[\int x^{3} \operatorname {arcsinh}\left (a x \right )^{n}d x\]
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\[ \int x^3 \text {arcsinh}(a x)^n \, dx=\int { x^{3} \operatorname {arsinh}\left (a x\right )^{n} \,d x } \]
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\[ \int x^3 \text {arcsinh}(a x)^n \, dx=\int x^{3} \operatorname {asinh}^{n}{\left (a x \right )}\, dx \]
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\[ \int x^3 \text {arcsinh}(a x)^n \, dx=\int { x^{3} \operatorname {arsinh}\left (a x\right )^{n} \,d x } \]
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Exception generated. \[ \int x^3 \text {arcsinh}(a x)^n \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int x^3 \text {arcsinh}(a x)^n \, dx=\int x^3\,{\mathrm {asinh}\left (a\,x\right )}^n \,d x \]
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